package solutions;


/*

The sum of the squares of the first ten natural numbers is, 
12 + 22 + ... + 102 = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025  385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

 */


public class Euler006 {

	/**
	 * @param args
	 */
	public static void main(String[] args) {
	
		//Sum of first N squares = (N * (N + 1) * (2N + 1)) / 6
		//Sum of first N numbers = N * (N + 1) / 2 
		
		final int N = 100;
		
		long result = (N * (N + 1) * (2*N + 1)) / 6 - (long) Math.pow((double)(N * (N + 1) / 2), 2.0);
		System.out.println("Result: " + Math.abs(result));
		

	}

}
